Three numbers, x, y and z are connected by the relationships y = \(\frac{4x}{9}\) + 1. If x = 99, Find z = \(\frac{4y}{9}\) + 1
 

  • A 6\(\frac{1}{3}\)
  • B 20
  • C 21
  • D 176\(\frac{4}{9}\)
  • E None of the above
jamb 1980mathematics

The correct answer is C. 21

Given that y = \(\frac{4x}{9}\) + 1 and x = 99, we can substitute x into the equation for y to get:

y = \(\frac{4*99}{9}\) + 1 = 44 + 1 = 45

Now, substituting y = 45 into the equation for z, we get:

z = \(\frac{4*45}{9}\) + 1 = 20 + 1 = 21

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