Arrange \(\frac{3}{5}\),\(\frac{9}{16}\), \(\frac{34}{59}\) and \(\frac{71}{97}\) in ascending order of magnitude.
The correct answer is B. \(\frac{9}{16}\), \(\frac{34}{59}\), \(\frac{3}{5}\) , \(\frac{71}{97}\)
To arrange the fractions \(\frac{3}{5}\), \(\frac{9}{16}\), \(\frac{34}{59}\), and \(\frac{71}{97}\) in ascending order, we can compare their decimal equivalents:
\(\frac{3}{5} = 0.6\)
\(\frac{9}{16} = 0.5625\)
\(\frac{34}{59} = 0.57627\)
\(\frac{71}{97} = 0.73196\)
So, in ascending order, the fractions are:
\(\frac{9}{16}\), \(\frac{34}{59}\), \(\frac{3}{5}\), \(\frac{71}{97}\)
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