In the figure, QRS is a line, PSQ = 35°, SPR = 30° and O is the centre of the circle. Find OQP.
 

  • A 35°
  • B 30°
  • C 130°
  • D 25°
  • E 65°
jamb 1984mathematics

The correct answer is D. 25°

< PSQ = 35°, < SPR = 30°
O is the centre of the circle, PRQ = 65°
< OQP = 90 - 65= 25°

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