In the diagram, QP//ST:PQR = 34° qrs = 73° and Rs = RT. Find SRT
 

  • A 68°
  • B 102°
  • C 107°
  • D 141°
jamb 1993mathematics

The correct answer is B. 102°

Construction joins R to P such that SRP = straight line
R = 180° - 107°
< p = 180° - (107° - 34°)
108 - 141° = 39°
Angle < S = 39° (corr. Ang.) But in \(\bigtriangleup\)SRT
< S = < T = 39°
SRT = 180 - (39° + 39°)
= 180° - 78°
= 102°

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