Evaluate \(\int\limits_0^\frac{\pi}{2}\) sinxdx
The correct answer is C. 1
The integral of \(\sin(x)\) from 0 to \(\frac{\pi}{2}\) is given by the definite integral:
\[\int\limits_0^\frac{\pi}{2} \sin(x) \, dx\]
The antiderivative of \(\sin(x)\) is \(-\cos(x)\), so we can evaluate the definite integral as follows:
\[-\cos\left(\frac{\pi}{2}\right) - (-\cos(0)) = 0 - (-1) = 1\]
So, the correct answer is 1.
Previous question Next questionWhat is Exam without Practice? With our customizable CBT practice tests, you’ll be well-prepared and ready to excel in your examsStart Practicing Now