Evaluate \(\int\limits_0^\frac{\pi}{2}\) sinxdx
 

  • A 2
  • B -1
  • C 1
  • D -2

The correct answer is C. 1

The integral of \(\sin(x)\) from 0 to \(\frac{\pi}{2}\) is given by the definite integral:

\[\int\limits_0^\frac{\pi}{2} \sin(x) \, dx\]

The antiderivative of \(\sin(x)\) is \(-\cos(x)\), so we can evaluate the definite integral as follows:

\[-\cos\left(\frac{\pi}{2}\right) - (-\cos(0)) = 0 - (-1) = 1\]

So, the correct answer is 1.

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