If \(f(x) = 3x^3 + 4x^2 + x - 8\), what is the value of f(-2)?
The correct answer is C. -18
To find the value of f(-2), we substitute -2 for x in the function:
\(f(x) = 3x^3 + 4x^2 + x - 8\).
Thus,
\(f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8 = -24 + 16 - 2 - 8 = -18\).
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