Factorise (4a + 3) \(^2\) - (3a - 2)\(^2\)

  • A (a + 1)(a + 5)
  • B (a - 5)(7a - 1)
  • C (a + 5)(7a + 1)
  • D a(7a + 1)

The correct answer is C. (a + 5)(7a + 1)

The given expression is a difference of squares, which can be factored using the formula \(a^2 - b^2 = (a - b)(a + b)\).

Let's set \(a = 4a + 3\) and \(b = 3a - 2\). Then the given expression becomes \(a^2 - b^2\), which can be factored as \((a - b)(a + b)\).

Substituting back gives:

\((4a + 3 - (3a - 2))(4a + 3 + (3a - 2)) = (a + 5)(7a + 1)\)

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