Find all real number x which satisfy the inequality \(\frac{1}{3}\) (x + 1) - 1 > \(\frac{1}{5}\)(x + 4)
The correct answer is D. x > 11
Let's solve the inequality step by step:
\(\frac{1}{3}(x + 1) - 1 > \frac{1}{5}(x + 4)\)
First, we'll clear the fractions by multiplying both sides by the least common multiple of 3 and 5, which is 15:
15 * \(\frac{1}{3}(x + 1) - 15 * 1 > 15 * \(\frac{1}{5}(x + 4)\)
5(x + 1) - 15 > 3(x + 4)
Now, let's simplify further:
5x + 5 - 15 > 3x + 12
Next, subtract 3x from both sides:
2x + 5 - 15 > 12
Now, subtract 5 from both sides:
2x - 10 > 12
Finally, add 10 to both sides to isolate 2x:
2x > 12 + 10
2x > 22
Now, divide by 2 to solve for x:
x > 11
So, the solution to the inequality is:
x > 11
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