factorize m\(^3\) - m\(^2\) + 2m - 2

  • A (m² + 1)(m - 2)
  • B (m - 1)(m + 1)(m + 2)
  • C (m - 2)(m + 1)(m - 1)
  • D (m² + 2)(m - 1)

The correct answer is D. (m² + 2)(m - 1)

The given expression is m³ - m² + 2m - 2. 

To factorize this expression, we can group the terms and factor by grouping:

m³ - m² + 2m - 2 = m²(m - 1) + 2(m - 1)

Now, we can factor out the common factor of (m - 1):

m²(m - 1) + 2(m - 1) = (m - 1)(m² + 2)

So, the factorized form of the expression is (m - 1)(m² + 2). 

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