factorize m\(^3\) - m\(^2\) + 2m - 2
The correct answer is D. (m² + 2)(m - 1)
The given expression is m³ - m² + 2m - 2.
To factorize this expression, we can group the terms and factor by grouping:
m³ - m² + 2m - 2 = m²(m - 1) + 2(m - 1)
Now, we can factor out the common factor of (m - 1):
m²(m - 1) + 2(m - 1) = (m - 1)(m² + 2)
So, the factorized form of the expression is (m - 1)(m² + 2).
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