In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. If the bisector of and M meets NO at P, calculate NP.

  • A 4.8 units
  • B 7.2 units
  • C 8.0 units
  • D 18.0 units
jamb 1999mathematics

The correct answer is B. 7.2 units

bisector theorem:

\(\frac{|MN|}{|MO|}\) = \(\frac{|PO|}{|NP|}\)

taking the bisected angle:x and y = |ON|=12

: x+y= 12

x =  12 - y

|PO| = 12 - y

\(\frac{6}{4}\)= \(\frac{12-y}{y}\)

6y = 4 (12-y)

6y = 48 - 4y

= 4.8

Recall that x+y= 12

12 - 4.8 =7.2

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