Evaluate \(\frac{(0.14^2 \times 0.275)}{7(0.02)}\) to 3 decimal places.

  • A 0.039
  • B 0.385
  • C 0.033
  • D 0.038
jamb 2001mathematics

The correct answer is A. 0.039

\(\frac{(0.14)^{2} \times 0.275}{7(0.02)} = \frac{(0.14)^{2} \times 0.275}{0.14}\)

= \(0.14 \times 0.275\)

= \(0.0385 \approxeq 0.039\)

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