A straight line makes an angle of 30° with the positive x-axis and cuts the y-axis at y = 5. Find the equation of the straight line.

  • A y = (x/10) + 5
  • B y = x + 5
  • C √3y = - x + 5√3
  • D √3y = x + 5√3

The correct answer is D. √3y = x + 5√3

The equation of a straight line can be written in the form \(y = mx + c\), where \(m\) is the slope of the line and \(c\) is the y-intercept. In this case, we are given that the line cuts the y-axis at \(y = 5\), so we know that \(c = 5\). We are also given that the line makes an angle of \(30°\) with the positive x-axis. The slope of a line is equal to the tangent of the angle it makes with the x-axis, so we have:

\(m = \tan(30°) = \frac{1}{\sqrt{3}}\)

Substituting these values into the equation for a straight line, we find that the equation of the line is:

\(y = \frac{1}{\sqrt{3}}x + 5\)

Multiplying both sides by \(\sqrt{3}\), we get:

\(\sqrt{3}y = x + 5\sqrt{3}\)

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