The bearings of P and Q from a common point N are 020° and 300° respectively. If P and Q are also equidistant from N, find the bearing of P from Q.

  • A 040°
  • B 070°
  • C 280°
  • D 320°
jamb 2001mathematics

The correct answer is C. 280°

The bearing of P from Q can be found by subtracting the bearing of P from N from the bearing of Q from N. Since the bearings of P and Q from N are 020° and 300° respectively, the bearing of P from Q is:

\(300° - 020° = 280°\)

So, the bearing of P from Q is 280°.

Previous question Next question