The slope of the tangent to the curve y = 3x\(^2\) - 2x + 5 at the point (1, 6) can be found by taking the derivative of the function with respect to x and evaluating it at x = 1. The derivative of y with respect to x is:

\(\frac{dy}{dx} = 6x - 2\)

Evaluating this at x = 1, we get:

\(\frac{dy}{dx} = 6(1) - 2 = 4\)

So the slope of the tangent to the curve y = 3x\(^2\) - 2x + 5 at the point (1, 6) is 4.