How many three-digit numbers can be formed from 32564 without repeating any of the digits?

  • A 120
  • B 10
  • C 20
  • D 60
jamb 2002mathematics

The correct answer is D. 60

Certainly! Here's the calculation written in MathJax:

The total number of permutations of \(n\) distinct objects is \(n!\). In this case, we have 5 distinct digits, so the total number of three-digit numbers that can be formed is \(\frac{5!}{(5 - 3)!}\).

Calculating:

\(\frac{5!}{(5 - 3)!} = \frac{5!}{2!} = \frac{5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{2 \cdot 1} = \frac{120}{2} = 60\).

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