Determine the maximum value of y = 3x- x
The correct answer is C. 4
y = 3x
- x
dy/dx = 6x - 3x
as dy/dx = 0
6x - 3x
= 0
3x (2 - x) = 0
this implies that 2 -x = 0 and 3x = 0
x = 2 (or) 0
But = dy/dx = 6x - 3x
d
y/dx
= 6 - 6x at x = 2
= 6 - 6(2)
= -6
y = 3x
- x
= 3(2)
- 2
= 12 - 8
= 4
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