If \(\log_{10} 2 = 0.3010\) and \(\log_{10} 3 = 0.4771\), evaluate \(\log_{10} 4.5\)

  • A 0.9542
  • B 0.6532
  • C 0.4771
  • D 0.3010
jamb 2005mathematics

The correct answer is B. 0.6532

Log102 = 0.3010 and Log103 = 0.4771

Log104.5 = Log1041/2

= Log109/2

= Log109 - Log102

= log103² - Log102

= 2Log103 - Log102

= 2(0.4771) - 0.3010

= 0.9542 - 0.3010

= 0.6532

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