. Three straight lines EF, GH and LK interest at O as shown above. If ∠KOF = 52∘ and ∠LOH = 85∘, calculate the size of ∠EOG.

  • A 26∘
  • B 43∘
  • C 52∘
  • D 85∘
jamb 2005mathematics

The correct answer is B. 43∘

∠GOK = 85

(vertical opposite angle ∠s)

∠EOG + ∠GOK + ∠KOF = 180 (∠s on a straight line)

∠EOg + 85

+ 52

= 180

∠EOG + 137

= 180

∠EOG = 43

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