In the diagram above, POQ is a diameter of the circle PQRS. If ∠PSR = 145°, find x°

  • A 55°
  • B 45°
  • C 35°
  • D 25°
jamb 2006mathematics

The correct answer is A. 55°

∠PSQ = 90° (∠ in semi circle)

∠PSQ + ∠QSR = 145°

90 + ∠QSR = 145

∠QSR = 145 - 90

∠QSR = 55°

BUt x° = ∠QSR (∠s in the same segment)

∴x° = 55°

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