If the locus of the points which are equidistant from point P and Q meets line PQ at point N, then PN equals

  • A NQ
  • B 1/4NQ
  • C 2NQ
  • D 1/2NQ

The correct answer is A. NQ

The locus of points equidistant from two points P and Q is the perpendicular bisector of the line segment PQ.

If the locus meets line PQ at point N, then PN is equal to NQ by definition of the perpendicular bisector.

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