In a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random. What is the probability that the fruit is either a grape or a banana

  • A 6/30
  • B 5/30
  • C 17/30
  • D 11/30
jamb 2007mathematics

The correct answer is C. 17/30

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes.

In this case, the total number of fruits is 6 (grapes) + 11 (bananas) + 13 (oranges) = 30 fruits.

The number of favorable outcomes (either a grape or a banana) is 6 (grapes) + 11 (bananas) = 17 fruits.

So, the probability that the fruit is either a grape or a banana is 17/30.

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