Find the locus of point equidistant from two straight lines y - 5 = 0 and y - 3 = 0

  • A y - 2 = 0
  • B y - 4 = 0
  • C y - 1 = 0
  • D y - 3 = 0

The correct answer is B. y - 4 = 0

The locus of points that are equidistant from two straight lines is the perpendicular bisector of the segment connecting any point on one line to any point on the other line.

Given the equations of the lines:

1. \(y - 5 = 0\) (Line 1)

2. \(y - 3 = 0\) (Line 2)

The points on these lines are \((x, 5)\) for Line 1 and \((x, 3)\) for Line 2.

Now, let's find the midpoint of the segment connecting these two points:

Midpoint = \(\left(\frac{x + x}{2}, \frac{5 + 3}{2}\right) = (x, 4)\)

The equation of the perpendicular bisector passing through the midpoint \((x, 4)\) will have the form y - 4 = 0.

Previous question Next question