Find the size of each exterior angle of a regular octagon
The correct answer is B. 45°
In a regular polygon, all exterior angles are congruent (have the same measure). The sum of the exterior angles of any polygon is always \(360^\circ\).
For a regular octagon, which has 8 sides, we can use the formula for the measure of each exterior angle:
\(\text{Measure of each exterior angle} = \frac{360^\circ}{\text{Number of sides}}\)
Substitute the values for a regular octagon (\(n = 8\)):
\(\text{Measure of each exterior angle} = \frac{360^\circ}{8} = 45^\circ\)
In a regular polygon, all exterior angles are congruent (have the same measure). The sum of the exterior angles of any polygon is always \(360^\circ\).
For a regular octagon, which has 8 sides, we can use the formula for the measure of each exterior angle:
\(\text{Measure of each exterior angle} = \frac{360^\circ}{\text{Number of sides}}\)
Substitute the values for a regular octagon (\(n = 8\)):
\(\text{Measure of each exterior angle} = \frac{360^\circ}{8} = 45^\circ\)
Therefore, the size of each exterior angle of a regular octagon is \(45^\circ\)
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