Find the size of each exterior angle of a regular octagon

  • A 51°
  • B 45°
  • C 40°
  • D 36°

The correct answer is B. 45°

In a regular polygon, all exterior angles are congruent (have the same measure). The sum of the exterior angles of any polygon is always \(360^\circ\).

For a regular octagon, which has 8 sides, we can use the formula for the measure of each exterior angle:

\(\text{Measure of each exterior angle} = \frac{360^\circ}{\text{Number of sides}}\)

Substitute the values for a regular octagon (\(n = 8\)):

\(\text{Measure of each exterior angle} = \frac{360^\circ}{8} = 45^\circ\)

In a regular polygon, all exterior angles are congruent (have the same measure). The sum of the exterior angles of any polygon is always \(360^\circ\).

For a regular octagon, which has 8 sides, we can use the formula for the measure of each exterior angle:

\(\text{Measure of each exterior angle} = \frac{360^\circ}{\text{Number of sides}}\)

Substitute the values for a regular octagon (\(n = 8\)):

\(\text{Measure of each exterior angle} = \frac{360^\circ}{8} = 45^\circ\)

Therefore, the size of each exterior angle of a regular octagon is \(45^\circ\)

Previous question Next question