Add \(1101_2,10111_2\) and \(111_2\)

  • A \(111011_2\)
  • B \(110110_2\)
  • C \(101011_2\)
  • D \(101010_2\)
jamb 2008mathematics

The correct answer is C. \(101011_2\)

11012 + 101112 + 1112 = 101011

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