On a pie chart, there are six sectors of which four angles are 30°, 45°, 60°, 90° and the remaining two angles are in the ratio 2:1. Find the smallest angles of the remaining two angles.
The correct answer is C. 45°
The sum of the angles in a pie chart is 360°, as it represents a full circle. Given that four angles are 30°, 45°, 60°, and 90°, their total is \(30° + 45° + 60° + 90° = 225°\).
Now, let the two remaining angles be \(2x\) and \(x\), where \(2x\) is twice the size of \(x\), and they are in a 2:1 ratio.
Adding up all the angles:
\(225° + 2x + x = 360°\)
Simplifying:
\(3x = 360° - 225°\)
\(3x = 135°\)
\(x = \frac{135°}{3}\)
x = 45°
So, the smallest angle of the remaining two angles is x = 45°.
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