Evaluate ∫sec\(^2\)θ dθ?

  • A sec θ tan θ + k
  • B tan θ + k
  • C 2sec θ + k
  • D sec θ + k
jamb 2009mathematics

The correct answer is B. tan θ + k

The integral of \(\sec^2\theta\) with respect to \(\theta\) can be evaluated using the formula:

\(\int \sec^2\theta \, d\theta = \tan\theta + k\)

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