The probability of a student passing any examination is 2/3. If the students takes three examination, what is the probability that he will not pass any of them?

  • A 2/3
  • B 4/9
  • C 8/27
  • D 1/27

The correct answer is D. 1/27

The probability of a student passing any examination is \( \frac{2}{3} \). The probability of not passing an examination is the complement of passing, which is \( 1 - \frac{2}{3} = \frac{1}{3} \).

Since the student takes three examinations, the probability of not passing any of them is the product of the probabilities of not passing each individual examination:

\( \left(\frac{1}{3}\right) \times \left(\frac{1}{3}\right) \times \left(\frac{1}{3}\right) = \frac{1}{27} \)

So, the probability that the student will not pass any of the examinations is 1/27.

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