What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?

  • A y = -χ + 6
  • B y = -χ - 6
  • C y = χ + 6
  • D y = χ - 6
jamb 2010mathematics

The correct answer is A. y = -χ + 6

Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1

Gradient bisector = -1

Equation of perpendicular bisector

y - y1 = m(χ - χ1

y - 4 = -χ + 2

y = -χ + 6

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