In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40°. Find ∠PSQ
The correct answer is A. 40°
R = P (base ∠s of isc Δ, ps = RS)
∴R = 40°
∠PSQ = R (∠s in alternate segment)
∴∠PSQ = 40°
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