In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40°. Find ∠PSQ

  • A 40°
  • B 30°
  • C 20°
  • D 10°

The correct answer is A. 40°

R = P (base ∠s of isc Δ, ps = RS)

∴R = 40°

∠PSQ = R (∠s in alternate segment)

∴∠PSQ = 40°

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