A triangle has vertices P(-1,6), Q(-3, -4) and R(1, -4).Find the midpoint of PQ and QR respectively.

  • A (0,-2) and (-1, -4)
  • B (-1,0) and (-1,-1)
  • C (-2,1) and (0,1)
  • D (-2,1) and (-1,-4)
jamb 2003mathematics

The correct answer is D. (-2,1) and (-1,-4)

Midpoint of PQ \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\

=\frac{-1+(-3)}{2};\frac{6-4}{2}\\

=\frac{-4}{2};\frac{2}{2}\\

=-2,1\)

Midpoint of QR = \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\

\frac{-3+1}{2};\frac{-4-4}{2}\\

\frac{-2}{2};\frac{-8}{2}\\

-1,-4\)

Midpoint of PQ and QR = (-2,1) and (-1,-4)

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