Factorize \(2y^2- 15xy + 18x^2\)
The correct answer is B. (2y - 3x) (y - 6x)
To factorize the expression \(2y^2 - 15xy + 18x^2\), we look for two binomials that, when multiplied, give us the original expression.
The expression can be factored as follows:
\(2y^2 - 15xy + 18x^2\)
First, let's look for two numbers that multiply to give \(2 \cdot 18 = 36\) and add up to give \(-15\). These numbers are \(-3\) and \(-12\).
Now we can write the middle term \(-15xy\) as the sum of \(-3xy\) and \(-12xy\):
\(2y^2 - 3xy - 12xy + 18x^2\)
Next, we group the terms and factor by grouping:
y(2y - 3x) - 6x(2y - 3x)
(2y - 3x)(y - 6x)
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