Factorize \(2y^2- 15xy + 18x^2\)

  • A (2y - 3x) (y + 6x)
  • B (2y - 3x) (y - 6x)
  • C (2y + 3x) (y - 6x)
  • D (3y + 2x) (y - 6x)

The correct answer is B. (2y - 3x) (y - 6x)

To factorize the expression \(2y^2 - 15xy + 18x^2\), we look for two binomials that, when multiplied, give us the original expression.

The expression can be factored as follows:

\(2y^2 - 15xy + 18x^2\)

First, let's look for two numbers that multiply to give \(2 \cdot 18 = 36\) and add up to give \(-15\). These numbers are \(-3\) and \(-12\).

Now we can write the middle term \(-15xy\) as the sum of \(-3xy\) and \(-12xy\):

\(2y^2 - 3xy - 12xy + 18x^2\)

Next, we group the terms and factor by grouping:

y(2y - 3x) - 6x(2y - 3x)

(2y - 3x)(y - 6x)

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