The determinant of a 3x3 matrix \(\begin{vmatrix} a & b & c \\ d & e & f \\ g & h & i \end{vmatrix}\) is given by the formula:

\(\text{Determinant} = a(ei - fh) - b(di - fg) + c(dh - eg)\)

Given the matrix \(\begin{vmatrix} 0 & 3 & 2 \\ 1 & 7 & 8 \\ 0 & 5 & 4 \end{vmatrix}\), we can substitute the values into the formula:

\(\text{Determinant} = 0(7 \cdot 4 - 8 \cdot 5) - 3(1 \cdot 4 - 8 \cdot 0) + 2(1 \cdot 5 - 7 \cdot 0)\)

Simplify the calculations:

\(\text{Determinant} = 0(28 - 40) - 3(4 - 0) + 2(5 - 0)\)

\(\text{Determinant} = 0 - 12 + 10\)

\(\text{Determinant} = -2\)

Therefore, the correct answer is:

D. -2