To find the remainder when \(6p^3 - p^2 - 47p + 30\) is divided by \(p - 3\), we can use the Remainder Theorem. The Remainder Theorem states that if you divide a polynomial \(f(x)\) by \(x - c\), the remainder is \(f(c)\).

In this case, we want to divide \(6p^3 - p^2 - 47p + 30\) by \(p - 3\). Therefore, we substitute \(p = 3\) into the polynomial to find the remainder:

\(6(3)^3 - (3)^2 - 47(3) + 30\)

\(6 \cdot 27 - 9 - 141 + 30\)

\(162 - 9 - 141 + 30\)

\(153 - 141 + 30\)

\(12 + 30\)

\(42\)

So, the remainder when \(6p^3 - p^2 - 47p + 30\) is divided by \(p - 3\) is 42.