T varies inversely as the cube of R. When R = 3, T = \(\frac{2}{81}\), find T when R = 2
The correct answer is B. \(\frac{1}{12}\)
Given that \(T\) varies inversely as the cube of \(R\), we can express this relationship as:
\[T = \frac{k}{R^3}\]
where \(k\) is the constant of variation.
We are given that when \(R = 3\) and \(T = \frac{2}{81}\), we can substitute these values into the equation to find \(k\):
\[\frac{2}{81} = \frac{k}{3^3}\]
\[\frac{2}{81} = \frac{k}{27}\]
\[k = \frac{2 \cdot 27}{81}\]
\[k = \frac{54}{81}\]
\[k = \frac{2}{3}\]
Now that we have the constant of variation \(k = \frac{2}{3}\), we can use it to find \(T\) when \(R = 2\):
\[T = \frac{\frac{2}{3}}{2^3}\]
\[T = \frac{\frac{2}{3}}{8}\]
\[T = \frac{2}{3} \cdot \frac{1}{8}\]
\[T = \frac{1}{12}\]
So, when \(R = 2\), \(T = \frac{1}{12}\).
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