If three unbiased coins are tossed, find the probability that they are all heads

  • A \(\frac{1}{2}\)
  • B \(\frac{1}{3}\)
  • C \(\frac{1}{9}\)
  • D \(\frac{1}{8}\)
jamb 2010mathematics

The correct answer is D. \(\frac{1}{8}\)

When three unbiased coins are tossed, there are a total of `2^3 = 8` equally likely outcomes, since each coin can land either heads or tails. Out of these 8 outcomes, only one outcome has all three coins landing heads: `(Heads, Heads, Heads)`. So, the probability of all three coins landing heads is `1/8`.

Therefore, the probability that three unbiased coins are all heads is 1/8.

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