Solve the simultaneous equations \(\frac{2}{x} - {\frac{3}{y}}\) = 2, \(\frac{4}{x} + {\frac{3}{y}}\) = 10

  • A x = \(\frac{3}{2}\), y = \(\frac{3}{2}\)
  • B x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)
  • C x = \(\frac{-1}{2}\), y = \(\frac{-3}{2}\)
  • D x = \(\frac{1}{3}\), y = \(\frac{3}{2}\)
jamb 1997mathematics

The correct answer is B. x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)

\(\frac{2}{x} - {\frac{3}{y}}\) = 2.....(1)

\(\frac{4}{x} + {\frac{3}{y}}\) = 10 ... (2)

(1) + (2):

\(\frac{6}{x}\) = 12 \(\to\) x = \(\frac{6}{12}\)

x = \(\frac{1}{2}\)

put x = \(\frac{1}{2}\) in equation (i)

= 4 - \(\frac{3}{y}\) = 2

= 4 - 2

= \(\frac{3}{y}\)

therefore y = \(\frac{3}{2}\)

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