Make F the subject of the formula t = \(\sqrt{\frac{v}{\frac{1}{f} + \frac{1}{g}}}\)
The correct answer is B. \(\frac{gt^2}{gv-t^2}\)
t = \(\sqrt{\frac{v}{\frac{1}{f} + \frac{1}{g}}}\)
t
= \(\frac{v}{\frac{1}{f} + \frac{1}{g}}\)
= \(\frac{vfg}{ftg}\)
\(\frac{1}{f} + \frac{1}{g}\) = \(\frac{v}{t^2}\)
= (g + f)t
= vfg
gt
= vfg - ft
gt
= f(vg - t
)
f = \(\frac{gt^2}{gv-t^2}\)
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