Let f(x) = 2x + 4 and g(x) = 6x + 7 here g(x) > 0. Solve the inequality \(\frac{f(x)}{g(x)}\)
The correct answer is C. x > - \(\frac{3}{4}\)
\(\frac{f(x)}{g(x)}\)
∴ \(\frac{2x +4}{6x + 7}\)
= 2x + 4
= 6x + 7 > 2x + 4
= 6x - 2x > 4 - 7
= 4x > -3
∴ x > -\(\frac{3}{4}\)
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