Let f(x) = 2x + 4 and g(x) = 6x + 7 here g(x) > 0. Solve the inequality \(\frac{f(x)}{g(x)}\)

  • A x
  • B x > - \(\frac{4}{3}\)
  • C x > - \(\frac{3}{4}\)
  • D x > - 12
jamb 1997mathematics

The correct answer is C. x > - \(\frac{3}{4}\)

\(\frac{f(x)}{g(x)}\)

∴ \(\frac{2x +4}{6x + 7}\)

= 2x + 4

= 6x + 7 > 2x + 4

= 6x - 2x > 4 - 7

= 4x > -3

∴ x > -\(\frac{3}{4}\)

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