Each of the base angles of a isosceles triangle is 58° and the verticles of the triangle lie on a circle. Determine the angle which the base of the triangle subtends at the centre of the circle.

  • A 128°
  • B 16°
  • C 64°
  • D 58°

The correct answer is A. 128°

Base angle of the triangle = 58°.

The third angle = 180° - (58° + 58°)

= 64°

Angle subtended at the centre = \(2 \times 64° = 128°\) (angle at the centre is twice the angle at the circumference).

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