A cone with the sector angle of 45° is cut out of a circle of radius r of the cone.

  • A \(\frac{r}{16}\) cm
  • B \(\frac{r}{6}\) cm
  • C \(\frac{r}{8}\) cm
  • D \(\frac{r}{2}\) cm
jamb 1997mathematics

The correct answer is C. \(\frac{r}{8}\) cm

The formula for the base radius of a cone formed from the sector of a circle = \(\frac{r \theta}{360°}\)

= \(\frac{r \times 45°}{360°}\)

= \(\frac{r}{8} cm\)

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