To find the derivative of cos(3x\(^2\) - 2x) with respect to x, we can use the chain rule.

The chain rule states that if we have a function f(g(x)), then the derivative of f(g(x)) with respect to x is f'(g(x)) g'(x).

In this case, we have f(x) = cos(x) and g(x) = 3x\(^2\) - 2x.

Taking the derivative of f(x) with respect to x, we get f'(x) = -sin(x).

Taking the derivative of g(x) with respect to x, we get g'(x) = 6x - 2.

Substituting these values into the chain rule formula, we get f'(g(x)) g'(x) = -sin(3x\(^2\) - 2x) (6x - 2).

So, the derivative of cos(3x\(^2\) - 2x) with respect to x is -(6x - 2)sin(3x\(^2\) - 2x). Therefore, the answer to Question 764 is D. -(6x - 2)sin(3x\(^2\) - 2x).