A number is selected at random between 10 and 20, both numbers inclusive. Find the probability that the number is an even number

  • A \(\frac{5}{11}\)
  • B \(\frac{1}{2}\)
  • C \(\frac{6}{11}\)
  • D \(\frac{7}{10}\)
jamb 1997mathematics

The correct answer is C. \(\frac{6}{11}\)

To find the probability that the randomly selected number is even, we need to determine the total number of even numbers between 10 and 20 (inclusive) and then divide it by the total number of possible numbers.

Even numbers between 10 and 20: 10, 12, 14, 16, 18, 20 (6 even numbers) Total number of possible numbers between 10 and 20: 20 - 10 + 1 = 11 numbers

Probability = (Number of even numbers) / (Total number of possible numbers) = 6 / 11

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