The latent heat of fusion of ice is 80cal g-1. How much heat is required to change 10g of ice at Q°C into water at the same temperature?

  • A 80 cal
  • B 10 cal
  • C 8 cal
  • D 800 cal
  • E 400 cal
jamb 1978physics

The correct answer is D. 800 cal

The heat required to change a substance from one state to another is given by the formula:
Q = m x L

where:Q = heat energy, m = mass of the substance, L = latent heat of fusion/vaporization

Given that the latent heat of fusion of ice is 80 cal/g and the mass of ice is 10g, the heat required to change 10g of ice into water at the same temperature is:

Q = 10g x 80 cal/g = 800 cal

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