Three 5 ohms resistors connected in parallel have a potential difference of 60v. applied across the combination. The current in each resistor is

  • A 4A
  • B 36A
  • C 12A
  • D 24A
  • E 10A

The correct answer is C. 12A

since they are in parallel, the same voltage across

= I1 = I2 = I3

I1 = \(\frac{V}{R_1}\)

\(\frac{60}{5}\) = 12A

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