an object 1cm high placed on the axis 15cm from a converging lens forms an image 30cm from the lens. The size of the image is
The correct answer is E. 2cm
\(\frac{\text{image distance}}{\text{object distance}}\) = \(\frac{\text{image height}}{\text{object height}}\)
\(\frac{30}{15}\) = \(\frac{\text{image height}}{1}\)
image height = 2cm
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