Calculate the gravitation force of attraction between two planets of 1024kg and 1027kg separated by a distance of 1020meters.

  • A 6.67N
  • B 6.56N
  • C 7.5N
  • D 8.6N
jamb 2015physics

The correct answer is A. 6.67N

F = (Gm1m2) ÷ r2

M1 = 1024Kg, M2 = 1027Kg , r = 102

(Note: the gravitational constant of G = \(6.67 × 10^{ 7ndash; 11}\) \( Nm^2/Kg^2 \)

F = \( (6.67 × 10^{– 11 + 24 + 27)} 10^40 = 6.67 × (10^40 ÷ 10^40)

= 6.67N

f = 6.67N

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