Given that 32.0g sulphur contains 6.02 x 10 23 sulphur atoms how many atoms are there in 2.70g of aluminium? {Al = 27, S =32}

  • A 6.02 x 10 23
  • B 3.01 x 1022
  • C 6.02 x 1022
  • D 5. 08 x 1022
  • E 3.01 x 1022
waec 1988chemistry

The correct answer is C. 6.02 x 1022

27g Aluminium = \(6.02 \times 10^{23}\)

1g Al = \(\frac{6.02 \times 10^{23}}{27}\)

2.7g Al = \(\frac{6.02 \times 10^{23}}{27} \times 2.7\)

= \(6.02 \times 10^{22} Al \) atoms

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