What quantity of copper will be deposited by the same quantity of electricity that deposited 9.0g of aluminum? (A = 27, Cu = 64)
The correct answer is B. 32g
Al has valency of 3+:
3F will deposit 27g
xF will deposit 9g
cross multiply â \(\frac{9g * 3F}{27g}\)
: 1F = 9g
Cu has valency of 2+:
2F will deposit 64g
1F will deposit xg
cross multiply â \(\frac{64g * 1F}{2F}\)
: 1F = 32g
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