What quantity of copper will be deposited by the same quantity of electricity that deposited 9.0g of aluminum? (A = 27, Cu = 64)

  • A 64g
  • B 32g
  • C 7.1g
  • D 6.4g
  • E 3.2g

The correct answer is B. 32g

Al has valency of 3+:

3F will deposit 27g

xF will deposit 9g

cross multiply â†’ \(\frac{9g * 3F}{27g}\)

: 1F = 9g

Cu has valency of 2+:

2F will deposit 64g

1F will deposit xg

cross multiply â†’ \(\frac{64g * 1F}{2F}\)

: 1F = 32g

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